A
anh_em_02


Tìm $x, y, z$ biết:
$\dfrac{y+z+1}{x}=\dfrac{x+z+2}{z}=\dfrac{x+y-3}{z}=\dfrac{1}{x+y+z}$
$\dfrac{y+z+1}{x}=\dfrac{x+z+2}{z}=\dfrac{x+y-3}{z}=\dfrac{1}{x+y+z}$
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