tim tham so

N

nguyenbahiep1

[TEX]y' = 4x^3 -16mx = 0 \\ \Leftrightarrow 4x (x^2 -4m)= 0 \\ TH_1 : m \leq 0 (T/M) \\ TH_2 m > 0 \\ \Rightarrow 2.\sqrt{m} > 2 \Rightarrow m > 1 \\ \Rightarrow : m \leq 0 , m > 1[/TEX]
 
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