tim so hang tong quat

N

ngomaithuy93

bai tap
1.cho tổng n so hang dau tien cua day~ so Sn=2n^2 +3n , n thuoc N*. chung minh rang day~ so Un la csc. tim so hang tong quat.
[TEX]S_{n+1}=2(n+1)^2+3(n+1)=2n^2+7n+5[/TEX]
[TEX]S_n=2n^2+3n[/TEX]
[TEX]S_{n-1}=2(n-1)^2+3(n-1)=2n^2-n-1[/TEX]
[TEX]S_{n-2}=2(n-2)^2+3(n-2)=2n^2-5n+2[/TEX]
N/x: [TEX]S_{n+1}-S_n=S_n-S_{n-1}+4=S_{n-1}-S_{n-2}+4[/TEX]
\Rightarrow Dãy [TEX]u_n[/TEX] là CSC với công sai d=4.
 
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