bạn tham khảo cách làm nhé:
[tex]U_{1}=\sqrt{2}=\sqrt{2[1+cos(\pi/2)]}=\sqrt{4[cos(\pi/4)^{2}]}=2cos(\pi/2^{2}) [/tex]
[tex]U_{2}=\sqrt{2+U_{1}}=\sqrt{2[1+cos(\pi/4)]}=\sqrt{4[cos(\pi/8)^{2}]}=2cos(\pi/2^{3})[/tex]
Vậy [tex]U_{n}=2cos(\pi/2^{n+1})[/tex]