Gọi [tex]M(a;\frac{a+2}{a-1})\\d(M;x+y=0)=\frac{\left | a+\frac{a+2}{a-1} \right |}{\sqrt{2}}\\\Leftrightarrow \frac{\left | a+\frac{a+2}{a-1} \right |}{\sqrt{2}}=\sqrt{2}\\\Leftrightarrow \left | a+\frac{a+2}{a-1} \right |=2\\TH1: a+\frac{a+2}{a-1}=2\Leftrightarrow VN \\TH2:a+\frac{a+2}{a-1}=-2\Leftrightarrow\left[\begin{array}{l} a=-2\\a=0 \end{array}\right.\Leftrightarrow \left[\begin{array}{l} M(-2;0)\\M(0;-2) \end{array}\right.[/tex]
Vậy $S=2$