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hotien217


Tìm bộ ba số nguyên dương (x;y;z) nghiệm đúng cả hai phương trình sau:
$\begin{array}{l} 5x^5 + 7(3x - y)^4 = 12098322\,\,\,\,\,\,(1) \\ z = \sqrt {xy^2 - x^2 y + 1909} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2) \\ \end{array}$
$\begin{array}{l} 5x^5 + 7(3x - y)^4 = 12098322\,\,\,\,\,\,(1) \\ z = \sqrt {xy^2 - x^2 y + 1909} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2) \\ \end{array}$