tim min,max

R

ran_mori_382

[TEX]y=\frac{2sinx+cosx+1}{sinx-2cosx+3}[/TEX]
\Leftrightarrow[TEX]sinx(2-y)+cosx(1+2y)=3y-1[/TEX]
để có no thì:[TEX](2-y)^2+(1+2y)^2\geq(3y-1)^2[/TEX]

[TEX]\Rightarrow \frac{-1}{2}\leq y \leq 2[/TEX]

->max=2 ,min=-1/2
 
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