Tìm Max

0

01263812493

cho [TEX]a+b \leq 1[/TEX]
tìm max:

[TEX]A=\frac{1}{a^3 + b^3} + \frac{1}{a^2b} + \frac{1}{ab^2}[/TEX]
 
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0

01263812493

cho [TEX]a,b \leq 1[/TEX]
tìm max:

[TEX]A=\frac{1}{a^3 + b^3} + \frac{1}{a^2b} + \frac{1}{ab^2}[/TEX]
:D
 
Q

quan8d

ai giúp tui dzới nào .........................................................>>>>><<<<<....................................
 
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