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hien_vuthithanh

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$(2.\dfrac{1}{a}+\sqrt{5-\dfrac{1}{a^2}})^2$ \leq 5.($\dfrac{1}{a^2}+5-\dfrac{1}{a^2})$=25
\Rightarrow$\dfrac{2}{a}+\sqrt{5-\dfrac{1}{a^2}} $\leq 5
dấu = \Leftrightarrow ...
 
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