Tìm Max, Min

V

vngocvien97

Dễ thấy:
$Min B=0$\Leftrightarrow$x=\pm \ \sqrt[]{5}+1$
Tìm $Max B$
Ta có: $$B^2=-x^2+2x+4=-(x-1)^2+5$$
Dễ thấy $Max B^2=5$\Rightarrow$Max B=\sqrt[]{5}$\Leftrightarrow$x=1$
 
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