[tex]\left\{\begin{matrix} y_1=2mx_1-2m+1\\ y_2=2mx_2-2m+1 \end{matrix}\right.\Rightarrow y_1+y_2=2m(x_1+x_2)-4m+2=10\Leftrightarrow 2m(x_1+x_2)-4m-8=0[/tex]
Xét phương trình hoành độ: [tex]x^2=2mx-2m+1\Leftrightarrow x^2-2mx+2m-1=0\Rightarrow x_1+x_2=2m\Rightarrow 4m^2-4m-8=0\Leftrightarrow m^2-m-2=0\Leftrightarrow (m-2)(m+1)=0\Leftrightarrow m=2 hoặc m=-1[/tex]