Tìm m, n để:

T

thaolovely1412

Câu 2
[TEX]n^5 + 1 =n^5+n^2-n^2+1= (n^3 + 1)n^2 - n^2 + 1 [/TEX]
[TEX]n^5+1\vdots\ n^3+1 \Rightarrow -n^2 + 1 = 0 [/TEX]
[TEX]\Leftrightarrow -n^2 =-1 [/TEX]
[TEX]\Leftrightarrow n^2 = 1 [/TEX]
[TEX]\Leftrightarrow n= 1[/TEX]
Vậy [TEX]n =\pm \ 1[/TEX]
 
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