tìm m để 2 nghiệm t/m cho trước

N

nguyenbahiep1

[TEX]\Delta' = m^2-2m+1 -2m^2+8m-2 = -m^2 +6m -1 > 0 \\ x_1.x_2 = \frac{m^2-4m+1}{2} \\ x_1 +x_2 = 1-m \\ | x_1.x_2 -2 (x_1+x_2)| = | \frac{m^2-4m+1}{2} +2m-2 | = |\frac{m^2-3}{2}| \geq 0 \Rightarrow m = \sqrt{3} (t/m) \\ m = -\sqrt{3} (L)[/TEX]
 
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