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riverflowsinyou1

$\dfrac{x}{1-x^{2}}=\dfrac{\dfrac{x^{2}}{2}}{x\dfrac{\sqrt{3}+1}{2}(1-x)\dfrac{\sqrt{3}-1}{2}(x+1)} \ge \dfrac{\dfrac{x^{2}}{2}}{\dfrac{(\sqrt{3})^{3}}{27}}=\dfrac{3\sqrt{3}}{2}x^{2}$
 
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