Tìm GTNN

E

eye_smile

$M=\dfrac{x^2-4x+2013}{x^2}=\dfrac{\dfrac{2009}{2013}x^2+\dfrac{4}{2013}(x-\dfrac{2013}{2})^2}{x^2} \ge \dfrac{2009}{2013}$

Dấu = xảy ra khi $x=\dfrac{2013}{2}$
 
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