Tìm GTNN

N

nguyenbahiep1

câu a

[LATEX]A = (x+\frac{y}{2})^2 + y^2 + 2012 - \frac{y^2}{4} \\ (x+\frac{y}{2})^2 + \frac{3}{4}.y^2 + 2012 \geq 2012 \\ \Rightarrow min A = 2012 \\ y = 0 , x= 0 [/LATEX]

câu b

[LATEX]B = 4(x-\frac{1}{8})^2 + (y- \frac{1}{2})^2 - \frac{21}{16} \geq - \frac{21}{16}\\ \Rightarrow min A = - \frac{21}{16} \\ y = \frac{1}{2} , x= \frac{1}{8} [/LATEX][
 
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