Điểm rơi [tex]x=y=\frac{1}{2}\Rightarrow x^2+y^2=2xy\Rightarrow \frac{1}{x^2+y^2}=\frac{1}{2xy}[/tex]
Ta có:[tex]A=\frac{1}{x^2+y^2}+\frac{6}{xy}=\frac{1}{x^2+y^2}+\frac{1}{2xy}+\frac{11}{2xy}\geq \frac{4}{x^2+y^2+2xy}+\frac{11}{2.\frac{(x+y)^2}{4}}=\frac{4}{(x+y)^2}+\frac{22}{(x+y)^2}=\frac{26}{(x+y)^2}\geq 26[/tex]