tìm GTLN, GTNN

B

buitrung2002

Ta có:
[tex]sin^{2}x+2sinx+2=(sinx+1)^{2}+1 \ge 1[/tex]
=>[tex] \frac{1}{(sinx+1)^{2}+1} \le 1[/tex]
vậy max = 1

[tex](sinx+1)^{2}+1 \geq 5[/tex]
=> min[tex] = \frac{1}{5}[/tex]

Note: đã gộp
 
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H

hn3

Bài 2 :

$y=sin(\frac{2x}{1+x^2})+cos(\frac{4x}{1+x^2})$

$cos(\frac{4x}{1+x^2})=cos(2.\frac{2x}{1+x^2})=1-2sin^2(\frac{2x}{1+x^2})$

==> $y=-2sin^2(\frac{2x}{1+x^2})+sin(\frac{2x}{1+x^2})+1$

Dễ r :-h
 
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