Ta có : $\dfrac{a+51}{49}+\dfrac{a+27}{73}+\dfrac{a+31}{69}+3=0$
$\iff (\dfrac{a+51}{49}+1)+(\dfrac{a+27}{73}+1)+(\dfrac{a+31}{69}+1)=0$
$\iff \dfrac{a+100}{49}+\dfrac{a+100}{73}+\dfrac{a+100}{69}=0$
$\iff (a+100)(\dfrac{1}{49}+\dfrac{1}{73}+\dfrac{1}{69})=0$
$\iff a+100=0$ (do $\dfrac{1}{49}+\dfrac{1}{73}+\dfrac{1}{69}\ne0$)
$\iff a=-100$