Tìm a,b

C

canary7311

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G

gaconkudo

Theo gt, ta có: abx3=(a+b)x2=>ab=(a+b)x2/3=>ab-a.2/3-b.2/3=0
=>a.(b-2/3)-b.2/3+4/9=4/9=>(a-2/3).(b-2/3)=4/9
Vì a khác b; a khác -b; a khác 0;b khác 0=>(a;b)=(1;2);(2;1)
 
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