Tích phân

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nguyenbahiep1

[laTEX]I = \int_{0}^{1} \frac{2^{\frac{x}{2}}}{(2^x-9).\sqrt{3 - \frac{4}{2^x}}} \\ \\ I = \int_{0}^{1} \frac{2^x}{(2^x-9).\sqrt{3.2^x - 4}} \\ \\ \sqrt{3.2^x - 4} = t \Rightarrow 2^x = \frac{t^2-4}{3} \Rightarrow 2^x.dx = \frac{2t}{3ln2}dt[/laTEX]
 
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