Tích phân

N

nguyenbahiep1

tích phân từ 0->1 của [(4x+1)/(x^3+2x^2+x+2)]dx

[laTEX]I = \int_{0}^{1}\frac{(4x+1)dx}{(x+2)(x^2+1)} = \frac{1}{5}(\int_{0}^{1}\frac{7x+6dx}{x^2+1} - \int_{0}^{1}\frac{7dx}{x+2} ) \\ \\ \frac{1}{5}\int_{0}^{1}\frac{7xdx}{x^2+1} + \frac{1}{5}\int_{0}^{1}\frac{6dx}{x^2+1} - \frac{1}{5}\int_{0}^{1}\frac{7dx}{x+2} \\ \\ \frac{1}{5}( \frac{7ln|x^2+1|}{2} + 6arctanx - 7ln|x+2| ) \big|_0^1[/laTEX]
 
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