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l94

[tex]u=ln^2x \to du=\frac{2lnx}{x}dx[/tex]
[tex]dv=x^3dx \to v=\frac{x^4}{4}[/tex]
[tex]I= \frac{x^4}{4}ln^2x- \frac{1}{2}\int_{}^{}x^3lnxdx[/tex]
[tex]I_2= \int_{}^{} x^3lnxdx[/tex]
[tex]u=lnx \to du=\frac{dx}{x}[/tex]
[tex]dv=x^3 \to v=\frac{x^4}{4}[/tex]
[tex] I_2=\frac{1}{4}x^4lnx-\frac{1}{4}\int x^3dx=\frac{1}{4}x^4lnx-\frac{x^4}{16}[/tex]
cận bạn tự thay.
 
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