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u=ln2x→du=2lnxxdxu=ln^2x \to du=\frac{2lnx}{x}dx
dv=x3dx→v=x44dv=x^3dx \to v=\frac{x^4}{4}
I=x44ln2x−12∫x3lnxdxI= \frac{x^4}{4}ln^2x- \frac{1}{2}\int_{}^{}x^3lnxdx
I2=∫x3lnxdxI_2= \int_{}^{} x^3lnxdx
u=lnx→du=dxxu=lnx \to du=\frac{dx}{x}
dv=x3→v=x44dv=x^3 \to v=\frac{x^4}{4}
I2=14x4lnx−14∫x3dx=14x4lnx−x416 I_2=\frac{1}{4}x^4lnx-\frac{1}{4}\int x^3dx=\frac{1}{4}x^4lnx-\frac{x^4}{16}
cận bạn tự thay.
 
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