tích phân

D

defhuong

[TEX]\int_{0}^{1}{\frac{X^3 dx}{\sqrt{X^2 +1}[/TEX]
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her.. câu này ngon :D:D:D:D
đặt [TEX]t =\sqrt{x^2+1}[/TEX] -> [TEX]t^2=x^2+1[/TEX] -->[TEX]2tdt=2xdx[/TEX]

[TEX]\int_{0}^{1}{\frac{X^3 dx}{\sqrt{X^2 +1}[/TEX]

[TEX]=\int_{}^{}\frac{x^2.xdx}{\sqrt{x^2+1}}[/TEX]

[TEX]=\int_{}^{}\frac{(t^2-1)tdt}{t}[/TEX]

[TEX]=\int_{}^{}(t^2-1)dt[/TEX]

dễ rồi nhá ;)
 
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