Tích Phân Lượng Giác

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nguyenbahiep1

[laTEX]cos^{10}+sin^{10} - sin^4x.cos^4x.(sin^2x+cos^2x) \\ \\ cos^6x.(cos^4x-sin^4x) + sin^6x.(sin^4x-cos^4x) \\ \\ (cos^4x-sin^4x)(cos^6x-sin^6x) = cos2x.cos2x.(cos^4x+sin^4x+sin^2x.cos^2x) \\ \\ \frac{1+cos4x}{2}. ( 1 - sin^2x.cos^2x) \\ \\ \frac{1+cos4x}{2}. ( 1 - \frac{1-cos4x}{4})[/laTEX]

đến đây nhân ra là xong rồi
 
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