tich phan kho

H

hoanghondo94

Thế này nhé ;)

[TEX]{\color{Blue} I=\int\frac{x^4 + 1}{x^6 + 1}dx =\int \frac{(x^4-x^2+1)+x^2}{(x^2+1)(x^4-x^2+1)}dx=\int \frac{dx}{x^2+1}+\int \frac{x^2dx}{x^6+1} \\\\ =\int \frac{dx}{x^2+1}+\frac{1}{3}\int \frac{d(x^3)}{x^6+1}=arctanx+\frac{1}{3}arctan(x^3)[/TEX]
:D:D:)
 
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