tích phân [12]

V

vivietnam

tính tích phân

[TEX]I=\int_{3}^{-1}\frac{x-3}{3sqrt{x+1}+x+3}dx[/TEX]
đặt [TEX]x+1=t^2 \Rightarrow dx=2tdt[/TEX]
[TEX]x|_{-1}^{3} \rightarrow \ t|_{0}^{2}[/TEX]
\Rightarrow [TEX]I=\int_{0}^{2} \frac{(t^2-4).2tdt}{t^2+3t+2}=\int_{0}^{2} \int (2t-6+\frac{6t+9}{t^2+3t+2}+\frac{3}{(t+1)(t+2)})dt=(t^2-6t+3.ln|t^2+3t+2|+3.ln|\frac{t+1}{t+2}|)|_{0}^{2}=................[/TEX]
 
0

08021994

đặt [TEX]x+1=t^2 \Rightarrow dx=2tdt[/TEX]
[TEX]x|_{-1}^{3} \rightarrow \ t|_{0}^{2}[/TEX]
\Rightarrow [TEX]I=\int_{0}^{2} \frac{(t^2-4).2tdt}{t^2+3t+2}=\int_{0}^{2} \int (2t-6+\frac{6t+9}{t^2+3t+2}+\frac{3}{(t+1)(t+2)})dt=(t^2-6t+3.ln|t^2+3t+2|+3.ln|\frac{t+1}{t+2}|)|_{0}^{2}=................[/TEX]
[TEX] t^2-4=(t+2)(t-2)[/TEX]
[TEX]t^2+3t+2=(t+1)(t+2)[/TEX], rút gọn cũng ra ^^:)
 
0

08021994

1. [TEX]\int_{0}^{\frac{\pi}{3}}\frac{xsin^2xdx}{sin2x.cos^2x}[/TEX]
:)
2. [TEX]\int_{0}^{\frac{\pi}{3}} \frac{1}{2sqrt{cos^3x}}[/TEX]
:(
 
T

tuyn

[TEX]I=\int\limits_{0}^{\frac{\pi}{3}}\frac{xsin^2x}{sin2xcos^2x}dx[/TEX]=[TEX]\int\limits_{0}^{\frac{\pi}{3}}\frac{xsinx}{2cos^3x}dx[/TEX]=[TEX]\int\limits_{0}^{\frac{\pi}{3}}\frac{-xd(cosx)}{2cos^3x}[/TEX]=[TEX]\int\limits_{0}^{\frac{\pi}{3}}xd(\frac{1}{4cos^2x})[/TEX]
 
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