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jessica96

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pe_lun_hp


BÀI 2: Tính [TEX]sin^2 10^o + sin^2 20^o +.....+ sin^2 70^o + sin^2 80^0[/TEX]

$sin^210^o+sin^220^o+...+sin^270^o+sin^280^o$

$=sin^2 10^o+sin^2 20^o+sin^2 30^o+sin^2 40^o+cos^2 40^o+cos^2 30^o+cos^2 20^o+cos^2 10^o$

$=(sin^2 10^o+cos^210^o)+(sin^220^o+cos^220^o)+(sin^230^0+cos^230^o)+(sin^240^o+cos^240^o)$

$=1+1+1+1$

$=4$
 
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