C
chopmaido
[TEX] \ sqrt{x+3}+ \sqrt[2]{3x+1}[/TEX] =4
bài 1
[TEX] \sqrt[2]{x+3}[/TEX] + [TEX] \sqrt[2]{3x+1}[/TEX] =4
[TEX] \Leftrightarrow ( \sqrt[2]{x+3} + \sqrt[2]{3x+1})^2 [/TEX] =16
[TEX] \Leftrightarrow 4x+4+2\sqrt{3x^2+10x+3}=16[/TEX]
[TEX] \Leftrightarrow 2x+2+\sqrt{3x^2+10x+3}= 8 [/TEX]
[TEX] \Leftrightarrow \sqrt[2]{3x^2+10x+3}=6-2x[/TEX]
[TEX] \Leftrightarrow 3x^2+10x+9=36-24x+4[/TEX]
Tự xử.
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