[tex]27^x-\frac{27}{27^x}=(3^x)^3-3.(3^x)^2.\frac{3}{3^x}+3.3^x.\frac{9}{(3^x)^2}-(\frac{3}{3^x})^3+9.3^x-\frac{27}{3^x}=(3^x-\frac{3}{3^x})^3+9(3^x-\frac{3}{3^x})[/tex]
Đặt [TEX]3^x-\frac{3}{3^x}=t[/TEX] ta được bpt: [tex]t^3-7t+6<0<=>(t-1)(t-2)(t+3)<0[/tex]