$ A \cap B = [10;15); A \cup B = (8;2011]; A \setminus B = (8;10); B \setminus A = [15;2011] \\ A \cap B = (2;3]; A \cup B = [-1;+\infty ); A \setminus B = (3;+\infty ); B \setminus A = [-1;2] \\ A \cap B = (1;4]; A \cup B = \mathbb{R}; A \setminus B = (-\infty ;1]; B \setminus A = (4;+\infty ] \\ A = [-1;5]; B = (2;8]\\ A \cap B = (2;5]; A \cup B = [-1;8]; A \setminus B = [-1;2]; B \setminus A = (5;8] $