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manhnguyen0164

Do I là trọng tâm nên $BI=\dfrac{2}{3}BB_1$; $CI=\dfrac{2}{3}CC_1$

$2(BI^2+CI^2)\ge (BI+CI)^2> BC^2$

$\iff (\dfrac{2}{3}BB_1)^2+(\dfrac{2}{3}CC_1)^2> \dfrac{BC^2}{2}$

$\iff BB_1^2+CC_1^2>\dfrac{9}{8}BC^2$
 
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