so sánh

P

pinkylun

Ta có:
2008A=$\dfrac{2008^{2009+2008}}{2008^{2009}+1}$

=$1+\dfrac{2007}{2008^{2009}+1}$

2008B=$\dfrac{2008^{2008}+2008}{2008^{2008}+1}$

=$1+\dfrac{2007}{2008^{2008}+1}$

=>2008A<2008B

=>A<B

xong rùi đó
 
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