so sánh hàm số luỹ thừa

N

natpl

Dang nay em khong hieu lam mong anh chi giai gium cho.Monh bai viet gui ve som,em sap phai kiem tra roi.
[tex]\sqrt{3}+\sqrt[3]{30} [/tex] and [tex]\sqrt[3]{63}[/tex]:)>-
Ta có: + [tex]\left\{ \begin{array}{l} \sqrt{3}> 1 \\ \sqrt[3]{30} >\sqrt[3]{27} = 3 \end{array} \right.[/tex]
\Rightarrow[tex]\sqrt{3}+\sqrt[3]{30}>4 [/tex]
+ [tex] \sqrt[3]{63}< \sqrt[3]{64} = 4[/tex]
Vậy [tex]\sqrt{3}+\sqrt[3]{30} > \sqrt[3]{63}[/tex]
 
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