Toán 12 Số phức

H

hn3

Cho số phức : [TEX]Z=1+\sqrt{3}.i[/TEX]

Tính [TEX]Z^5[/TEX] ?

Giải :

[TEX]r=\sqrt{1^2+(\sqrt{3})^2}=2[/TEX]

[TEX]tan\varphi =\sqrt{3}[/TEX]

[TEX]==> \varphi=\frac{\pi}{3}[/TEX]

[TEX]Z^5=2^5.(cos{\frac{5\pi}{3}}+i.sin{\frac{5\pi}{3}})[/TEX]

:)
 
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