ĐKXĐ [tex]x\neq 1[/tex]
Ta có: [tex]\frac{4x-4}{1-2x+x^2}=\frac{4.(x-1)}{(x-1)^2}=\frac{4}{x-1}[/tex]
Để [tex]\frac{4}{x-1}<0[/tex] thì x-1 > 0 <=> x>1
ĐKXĐ [tex]x\neq 1[/tex]
Ta có: [tex]\frac{4x-4}{1-2x+x^2}=\frac{4.(x-1)}{(x-1)^2}=\frac{4}{x-1}[/tex]
Để [tex]\frac{4}{x-1}<0[/tex] thì x-1 > 0 <=> x>1