[TEX]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}=\frac{(1-\sqrt{3})^2}{2}[/TEX]
tương tự
=>A=[tex]1+\frac{\sqrt{3}-1}{\sqrt2}+\frac{\sqrt{4}-\sqrt{2}}{\sqrt2}+...+\frac{\sqrt{2018}-\sqrt{2016}}{\sqrt2}=\frac{\sqrt2+\sqrt{3}+...+\sqrt{2018}-1-\sqrt{2}-...-\sqrt{2016}}{\sqrt2}=\frac{\sqrt{2018}+\sqrt{2017}-1}{\sqrt2}[/tex]