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Bạn chú ý tới $9x - 1 = (3\sqrt{x} + 1)(3\sqrt{x} - 1)$
Vậy $P = \dfrac{9x - 1 - 2\sqrt{x}(3\sqrt{x} - 1) + \sqrt{x} + 1}{9x - 1} . \dfrac{3\sqrt{x} + 1}{9\sqrt{x} + 6 - 3(3\sqrt{x} + 1)}$
$ = \dfrac{3\sqrt{x}(\sqrt{x} + 1)}{9x - 1}.\dfrac{3\sqrt{x} + 1}{3}$
Tự làm tiếp