Rút gọn $\frac{2x\sqrt{x }+1 - \sqrt{x}}{1+x\sqrt{x}}$

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1um1nhemtho1

$\frac{2x\sqrt{x }+1 - \sqrt{x}}{1+x\sqrt{x}}$

tử $2x\sqrt{x }+1 - \sqrt{x}= 2x\sqrt{x }+2 -1 - \sqrt{x}$
$= 2(x\sqrt{x }+1) - 1 - \sqrt{x}$
$= 2(1+\sqrt{x})(1-\sqrt{x}+x) - (1+\sqrt{x})$
$= (1+\sqrt{x})(1-2\sqrt{x}+2x)$

rồi mẫu $1+x\sqrt{x}=(1+\sqrt{x})(1-\sqrt{x}+x)$
rồi thay vào và rút gọn :)
 
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