$(x^3-3x+2)(y^3-3y+2)(z^3-3z+2)$
$=x^3y^3-3xy^3+2y^3-3x^3y+9xy-6y+2x^3z^3-6xz^3+4z^3-3x^3y^3+9xy^3-6y^3+9x^3y-27xy+18y-6x^3z+18xz-12z+2x^3y^3-6xy^3+4y^3-6x^3y+18xy-12xy+4x^3-12x+8$ $\text{(Đoạn này tắt xíu)}$
$=2x^3z^3-6x^3z-6xz^3+4x^3+4z^3-12xy+18xz+12y-12x-12z+8$