1. [tex](\sqrt{12}+\sqrt{27}-\sqrt{3}):\sqrt{3}=(2\sqrt{3}+3\sqrt{3}-\sqrt{3}):\sqrt{3}=4\sqrt{3} : \sqrt{3}=4[/tex]
2. [tex](\sqrt{4}-\sqrt{16}+\sqrt{25}).\sqrt{4}=(2-4+5)\sqrt{4}=3.2=6[/tex]
3. [tex]\sqrt{\frac{3}{4}}+\sqrt{\frac{1}{3}}+\sqrt{\frac{1}{12}}=\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{3}+\frac{\sqrt{3}}{6}=\frac{3\sqrt{3}+2\sqrt{3}+\sqrt{3}}{6}=\frac{6\sqrt{3}}{6}=\sqrt{3}[/tex]