[tex]\sqrt{\frac{a}{1+2b+b^{2}}} . \sqrt{\frac{4a+8ab+4ab^{2}}{225}}[/tex]
[tex]\sqrt{\frac{a}{1+2b+b^2}}.\sqrt{\frac{4a+8ab+4ab^2}{225}}\\=\sqrt{\frac{a}{(b+1)^2}}.\sqrt{\frac{4a(b+1)^{2}}{15^{2}}}\\=\sqrt{\frac{4a^2(b-1)^2}{(b+1)^2.15^2}}=\frac{\left | 2a \right |}{15}[/tex]