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niemkieuloveahbu

[TEX]PT \Leftrightarrow 2sinxcos2x+2sinxcosxcos2x=4sinxcos2xcos^2x\\ \Leftrightarrow sinxcos2x(1+cosx-2cos^2x)=0\\ \Leftrightarrow \left[sinx=0\\cos2x=0\\2cos^2x-cosx-1=0\right.\\ \Leftrightarrow \[ x=k\pi\\x=\frac{\pi}{4}+k\frac{\pi}{2}\\x=+-\frac{2\pi}{3}+k2\pi[/TEX]
 
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