PT vô tỉ!

L

locxoaymgk

DK: [TEX]x\geq 4.[/TEX]

[TEX]PT \Leftrightarrow \sqrt{2(x^2-16)}+(x-3)>7-x[/TEX]

[TEX] \Leftrightarrow \sqrt{2(x^2-16)}>10-2x.[/TEX]

[TEX]\Leftrightarrow \left[\begin{x>5}\\{\left{\begin{4 \leq x \leq 5}\\{2(x^2-16)>(10-2x)^2}[/TEX]
 
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