PT luong giac khó

C

connguoivietnam

[TEX]cosx + cos3x + 2cos5x=0[/TEX]

[TEX]cosx+cos3x+cos5x+cos5x=0[/TEX]

[TEX]2cos3xcos2x+2cos4xcosx=0[/TEX]

[TEX]cosx(4cos^2x-3)cos2x+cos4xcosx=0[/TEX]

[TEX]cosx[(4cos^2x-3)cos2x+cos4x]=0[/TEX]

[TEX]cosx=0[/TEX]

[TEX](4cos^2x-3)cos2x+cos4x=0[/TEX]

[TEX][2(cos2x+1)-3]cos2x+2cos^22x-1=0[/TEX]

[TEX]2cos^22x-cos2x+2cos^22x-1=0[/TEX]

[TEX]4cos^22x-cos2x-1=0[/TEX]
 
H

huutrang93

giải PT: cosx + cos3x + 2cos5x= 0 help me! :confused::confused::confused::confused::confused::confused::confused::confused::confused::confused::confused:

cách 2

[TEX]cosx+cos3x+2cos5x=0[/TEX]

[TEX]<=> cosx+cos3x+2cos(x+4x)=0[/TEX]

[TEX]<=>2cos2xcosx+2cosxcos4x-2sinxsin4x=0[/TEX]

[TEX]<=>cos2xcosx+cosxcos4x-4sin^2xcosxcos2x=0[/TEX]

[TEX]<=>cosx(cos2x+cos4x-4sin^2xcos2x)=0[/TEX]

[TEX]=> x[/TEX]
 
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H

huutrang93

giải PT: cosx + cos3x + 2cos5x= 0 help me! :confused::confused::confused::confused::confused::confused::confused::confused::confused::confused::confused:

cách 3
[TEX]<=> cosx+4cos^3x-3cosx+2cos5x=0[/TEX]

[TEX]<=>4cos^3x-2cosx+2cos5x=0[/TEX]

[TEX]<=>2cos^3x-(cosx-cos5x)=0[/TEX]

[TEX]<=>2cos^3x-[-2sin3xsin(-2x)]=0[/TEX]

[TEX]<=>2cos^3x-2sin3xsin2x=0[/TEX]

[TEX]<=>cos^3x-sin3xsin2x=0[/TEX]

[TEX]<=>cosx(cos^2x-2sin3xsinx)=0[/TEX]

[TEX]cosx=0[/TEX]

hoặc

[TEX]2sin^2x-1-2(3sinx-4sin^3x)sinx=0[/TEX]

[TEX]<=>2sin^2x-1-6sin^2x+8sin^4x=0[/TEX]

[TEX]=> x[/TEX]
 
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