Đặt [tex]\sqrt[3]{1+\sqrt{x}}=a,\sqrt[3]{1-\sqrt{x}}=b\Rightarrow \left\{\begin{matrix} a+b=2\\ a^3+b^3=2 \end{matrix}\right.\Rightarrow \left\{\begin{matrix} a=2-b\\ (2-b)^3+b^3=2 \end{matrix}\right.\Rightarrow \left\{\begin{matrix} a=2-b\\ 6b^2-12b+6=0 \end{matrix}\right.\Rightarrow \left\{\begin{matrix} a=2-b\\ 6(b-1)^2=0 \end{matrix}\right.\Rightarrow \left\{\begin{matrix} a=1\\ b=1 \end{matrix}\right.\Rightarrow \sqrt{x}=0\Rightarrow x=0[/tex]