H
hoangduong081198


giải phương trình:
1. $(\sqrt[2]{10} + 3)^x + (\sqrt[2]{10} - 3)^x = \frac{3}{2}.3^x$
2. $3^x.8^\frac{x}{x+ 2} = 6$
1. $(\sqrt[2]{10} + 3)^x + (\sqrt[2]{10} - 3)^x = \frac{3}{2}.3^x$
2. $3^x.8^\frac{x}{x+ 2} = 6$
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