Đặt [tex]\alpha =\frac{3\Pi }{10}-\frac{x}{2}\rightarrow x=\frac{3\Pi }{5}-2\alpha[/tex]
[tex]\rightarrow \frac{\Pi }{10}+\frac{3x}{2}=\frac{\Pi }{10}+\frac{3}{2}(\frac{3\Pi }{5}-2\alpha )=\Pi -3\alpha[/tex]
[tex]pt\Leftrightarrow sin\alpha =\frac{1}{2}sin(\Pi -3\alpha )=\frac{1}{2}sin3\alpha \Leftrightarrow sin\alpha =\frac{1}{2}(3sin\alpha -4sin^{3}\alpha )\rightarrow \begin{bmatrix} sin\alpha =0 & \\ sin\alpha =\pm \frac{1}{2}& \end{bmatrix}...[/tex]