5[sinx+(cos3x+sin3x)/(1+2sin2x)]=cos2x+3
<=> 5.[sinx + 2sinx.sin2x + cos 3x + sin 3x]/(1+ 2sin 2x) = cos 2x +3
<=> 5.(sin x + cos x - cos 3x + cos 3x + sin 3x) = (1+2sin 2x) ( cos 2x + 3)
<=> 5(sin x +5 sin 3x + 5 cosx = (1 + 2sin 2x)(cos 2x + 3)
<=> 10.sin 2x . cosx + 5.cos x = (1 +2 sin 2x)(cos 2x + 3)
<=> 5 cos x(2 sin 2x +1 ) = (1 + 2sin 2x)(cos 2x + 3)
<=> (2sin 2x + 1)(5 cos x - cos 2x + 3 ) = 0
<=> (2sin 2x + 1)( - 2cos^2x + 5.cos x + 4) = 0
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