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H

haminhtribs

123456

x^4 + 64 =x^4 + 16x^2 + 8^2 _ 16x^2 = (x^2 + 8)^2 _ (4x)^2
= (x^2 +8 _4)(x^2 +8 +4)=(x^2 +4 )(x^2 + 12):p:p:p:p:p
 
N

nom1

$x^4 + 64$

$ = x^4 + 16x^2 + 8^2 - 16x^2 $

$= (x^2 + 8)^2 - (4x)^2 $

$= (x^2 +8 -4x)(x^2 +8 +4x)$

$=(x^2 - 4x +8)(x^2 + 4x +8)$
 
S

soccan

=))
$x^4+64\\
=x^4+4x^3+8x^2-4x^3-16x^2-32x+8x^2+32x+64\\
=x^2(x^2+4x+8)-4x(x^2+4x+8)+8(x^2+4x+8)\\
=(x^2+4x+8)(x^2-4x+8)$
em quá rảnh =))
 
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